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(X-8)(5X+14)=0
We multiply parentheses ..
(+5X^2+14X-40X-112)=0
We get rid of parentheses
5X^2+14X-40X-112=0
We add all the numbers together, and all the variables
5X^2-26X-112=0
a = 5; b = -26; c = -112;
Δ = b2-4ac
Δ = -262-4·5·(-112)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2916}=54$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-54}{2*5}=\frac{-28}{10} =-2+4/5 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+54}{2*5}=\frac{80}{10} =8 $
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