(5y-10)=3(-2y+5)

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Solution for (5y-10)=3(-2y+5) equation: 



(5y-10)=3(-2y+5)

We move all terms to the left:

(5y-10)-(3(-2y+5))=0

We get rid of parentheses

5y-(3(-2y+5))-10=0



We calculate terms in parentheses: -(3(-2y+5)), so:

3(-2y+5)

We multiply parentheses

-6y+15

Back to the equation:

-(-6y+15)



We get rid of parentheses

5y+6y-15-10=0

We add all the numbers together, and all the variables

11y-25=0

We move all terms containing y to the left, all other terms to the right

11y=25

y=25/11

y=2+3/11

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