3(-6-2x)=4(-x-2)

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Solution for 3(-6-2x)=4(-x-2) equation: 



3(-6-2x)=4(-x-2)

We move all terms to the left:

3(-6-2x)-(4(-x-2))=0

We add all the numbers together, and all the variables

3(-2x-6)-(4(-1x-2))=0

We multiply parentheses

-6x-(4(-1x-2))-18=0



We calculate terms in parentheses: -(4(-1x-2)), so:

4(-1x-2)

We multiply parentheses

-4x-8

Back to the equation:

-(-4x-8)



We get rid of parentheses

-6x+4x+8-18=0

We add all the numbers together, and all the variables

-2x-10=0

We move all terms containing x to the left, all other terms to the right

-2x=10

x=10/-2

x=-5

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