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x+35=5/3x
We move all terms to the left:
x+35-(5/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x-(+5/3x)+35=0
We get rid of parentheses
x-5/3x+35=0
We multiply all the terms by the denominator
x*3x+35*3x-5=0
Wy multiply elements
3x^2+105x-5=0
a = 3; b = 105; c = -5;
Δ = b2-4ac
Δ = 1052-4·3·(-5)
Δ = 11085
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-\sqrt{11085}}{2*3}=\frac{-105-\sqrt{11085}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+\sqrt{11085}}{2*3}=\frac{-105+\sqrt{11085}}{6} $
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