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(8+u)(4u+5)=0
We add all the numbers together, and all the variables
(u+8)(4u+5)=0
We multiply parentheses ..
(+4u^2+5u+32u+40)=0
We get rid of parentheses
4u^2+5u+32u+40=0
We add all the numbers together, and all the variables
4u^2+37u+40=0
a = 4; b = 37; c = +40;
Δ = b2-4ac
Δ = 372-4·4·40
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-27}{2*4}=\frac{-64}{8} =-8 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+27}{2*4}=\frac{-10}{8} =-1+1/4 $
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