(m-15)/2=(3+m)/(10)+3

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Solution for (m-15)/2=(3+m)/(10)+3 equation: 



(m-15)/2=(3+m)/(10)+3

We move all terms to the left:

(m-15)/2-((3+m)/(10)+3)=0

We add all the numbers together, and all the variables

(m-15)/2-((m+3)/10+3)=0

We calculate fractions


(10m-150)/()+(-((m+3)*2)/()=0



We calculate terms in parentheses: +(-((m+3)*2)/(), so:

-((m+3)*2)/(

We multiply all the terms by the denominator


-((m+3)*2)



We calculate terms in parentheses: -((m+3)*2), so:

(m+3)*2

We multiply parentheses

2m+6

Back to the equation:

-(2m+6)



We get rid of parentheses

-2m-6

Back to the equation:

+(-2m-6)



We get rid of parentheses

(10m-150)/()-2m-6=0

We multiply all the terms by the denominator


(10m-150)-2m*()-6*()=0

We add all the numbers together, and all the variables

(10m-150)-2m*()=0

We get rid of parentheses

10m-2m*()-150=0

We move all terms containing m to the left, all other terms to the right

10m-2m*()=150

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