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x(5x-5)=1050
We move all terms to the left:
x(5x-5)-(1050)=0
We multiply parentheses
5x^2-5x-1050=0
a = 5; b = -5; c = -1050;
Δ = b2-4ac
Δ = -52-4·5·(-1050)
Δ = 21025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{21025}=145$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-145}{2*5}=\frac{-140}{10} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+145}{2*5}=\frac{150}{10} =15 $
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