(3x+40)+x+(11x-60)=180

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Solution for (3x+40)+x+(11x-60)=180 equation: 



(3x+40)+x+(11x-60)=180

We move all terms to the left:

(3x+40)+x+(11x-60)-(180)=0

We add all the numbers together, and all the variables

x+(3x+40)+(11x-60)-180=0

We get rid of parentheses

x+3x+11x+40-60-180=0

We add all the numbers together, and all the variables

15x-200=0

We move all terms containing x to the left, all other terms to the right

15x=200

x=200/15

x=13+1/3

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