(8+2x)(26+2x)=760

Solution for (8+2x)(26+2x)=760 equation:

(8+2x)(26+2x)=760

We move all terms to the left:

(8+2x)(26+2x)-(760)=0

We add all the numbers together, and all the variables

(2x+8)(2x+26)-760=0

We multiply parentheses ..

(+4x^2+52x+16x+208)-760=0

We get rid of parentheses

4x^2+52x+16x+208-760=0

We add all the numbers together, and all the variables

4x^2+68x-552=0

a = 4; b = 68; c = -552;
Δ = b2-4ac
Δ = 682-4·4·(-552)
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13456}=116$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(68)-116}{2*4}=\frac{-184}{8}
=-23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(68)+116}{2*4}=\frac{48}{8}
=6
$