3(4+5c)=-(12c+18)

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Solution for 3(4+5c)=-(12c+18) equation: 



3(4+5c)=-(12c+18)

We move all terms to the left:

3(4+5c)-(-(12c+18))=0

We add all the numbers together, and all the variables

3(5c+4)-(-(12c+18))=0

We multiply parentheses

15c-(-(12c+18))+12=0



We calculate terms in parentheses: -(-(12c+18)), so:

-(12c+18)

We get rid of parentheses

-12c-18

Back to the equation:

-(-12c-18)



We get rid of parentheses

15c+12c+18+12=0

We add all the numbers together, and all the variables

27c+30=0

We move all terms containing c to the left, all other terms to the right

27c=-30

c=-30/27

c=-1+1/9

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