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(7x-5)(3x+2)=0
We multiply parentheses ..
(+21x^2+14x-15x-10)=0
We get rid of parentheses
21x^2+14x-15x-10=0
We add all the numbers together, and all the variables
21x^2-1x-10=0
a = 21; b = -1; c = -10;
Δ = b2-4ac
Δ = -12-4·21·(-10)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-29}{2*21}=\frac{-28}{42} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+29}{2*21}=\frac{30}{42} =5/7 $
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