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1+2(6v-2)=-3(4v-1)+6v
We move all terms to the left:
1+2(6v-2)-(-3(4v-1)+6v)=0
We multiply parentheses
12v-(-3(4v-1)+6v)-4+1=0
We calculate terms in parentheses: -(-3(4v-1)+6v), so:We add all the numbers together, and all the variables
-3(4v-1)+6v
We add all the numbers together, and all the variables
6v-3(4v-1)
We multiply parentheses
6v-12v+3
We add all the numbers together, and all the variables
-6v+3
Back to the equation:
-(-6v+3)
12v-(-6v+3)-3=0
We get rid of parentheses
12v+6v-3-3=0
We add all the numbers together, and all the variables
18v-6=0
We move all terms containing v to the left, all other terms to the right
18v=6
v=6/18
v=1/3
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