-2(u+4)=4u-6+2(3u+7)

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Solution for -2(u+4)=4u-6+2(3u+7) equation:



-2(u+4)=4u-6+2(3u+7)
We move all terms to the left:
-2(u+4)-(4u-6+2(3u+7))=0
We multiply parentheses
-2u-(4u-6+2(3u+7))-8=0
We calculate terms in parentheses: -(4u-6+2(3u+7)), so:
4u-6+2(3u+7)
determiningTheFunctionDomain 4u+2(3u+7)-6
We multiply parentheses
4u+6u+14-6
We add all the numbers together, and all the variables
10u+8
Back to the equation:
-(10u+8)
We get rid of parentheses
-2u-10u-8-8=0
We add all the numbers together, and all the variables
-12u-16=0
We move all terms containing u to the left, all other terms to the right
-12u=16
u=16/-12
u=-1+1/3

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