5v+2-2(-2v-4)=3(v-2)

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Solution for 5v+2-2(-2v-4)=3(v-2) equation: 



5v+2-2(-2v-4)=3(v-2)

We move all terms to the left:

5v+2-2(-2v-4)-(3(v-2))=0

We multiply parentheses

5v+4v-(3(v-2))+8+2=0



We calculate terms in parentheses: -(3(v-2)), so:

3(v-2)

We multiply parentheses

3v-6

Back to the equation:

-(3v-6)



We add all the numbers together, and all the variables

9v-(3v-6)+10=0

We get rid of parentheses

9v-3v+6+10=0

We add all the numbers together, and all the variables

6v+16=0

We move all terms containing v to the left, all other terms to the right

6v=-16

v=-16/6

v=-2+2/3

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