(6y+3)+(3y+4)=13y-17

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Solution for (6y+3)+(3y+4)=13y-17 equation: 



(6y+3)+(3y+4)=13y-17

We move all terms to the left:

(6y+3)+(3y+4)-(13y-17)=0

We get rid of parentheses

6y+3y-13y+3+4+17=0

We add all the numbers together, and all the variables

-4y+24=0

We move all terms containing y to the left, all other terms to the right

-4y=-24

y=-24/-4

y=+6

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