3(4s-7)=6(s+2)

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Solution for 3(4s-7)=6(s+2) equation: 



3(4s-7)=6(s+2)

We move all terms to the left:

3(4s-7)-(6(s+2))=0

We multiply parentheses

12s-(6(s+2))-21=0



We calculate terms in parentheses: -(6(s+2)), so:

6(s+2)

We multiply parentheses

6s+12

Back to the equation:

-(6s+12)



We get rid of parentheses

12s-6s-12-21=0

We add all the numbers together, and all the variables

6s-33=0

We move all terms containing s to the left, all other terms to the right

6s=33

s=33/6

s=5+1/2

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