12(x+5)=8(x-8)-4

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Solution for 12(x+5)=8(x-8)-4 equation: 



12(x+5)=8(x-8)-4

We move all terms to the left:

12(x+5)-(8(x-8)-4)=0

We multiply parentheses

12x-(8(x-8)-4)+60=0



We calculate terms in parentheses: -(8(x-8)-4), so:

8(x-8)-4

We multiply parentheses

8x-64-4

We add all the numbers together, and all the variables

8x-68

Back to the equation:

-(8x-68)



We get rid of parentheses

12x-8x+68+60=0

We add all the numbers together, and all the variables

4x+128=0

We move all terms containing x to the left, all other terms to the right

4x=-128

x=-128/4

x=-32

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