4y-6(y+2)=1

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Solution for 4y-6(y+2)=1 equation: 



4y-6(y+2)=1

We move all terms to the left:

4y-6(y+2)-(1)=0

We multiply parentheses

4y-6y-12-1=0

We add all the numbers together, and all the variables

-2y-13=0

We move all terms containing y to the left, all other terms to the right

-2y=13

y=13/-2

y=-6+1/2

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