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(5/3n)-17=3n-25
We move all terms to the left:
(5/3n)-17-(3n-25)=0
Domain of the equation: 3n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
(+5/3n)-(3n-25)-17=0
We get rid of parentheses
5/3n-3n+25-17=0
We multiply all the terms by the denominator
-3n*3n+25*3n-17*3n+5=0
Wy multiply elements
-9n^2+75n-51n+5=0
We add all the numbers together, and all the variables
-9n^2+24n+5=0
a = -9; b = 24; c = +5;
Δ = b2-4ac
Δ = 242-4·(-9)·5
Δ = 756
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{756}=\sqrt{36*21}=\sqrt{36}*\sqrt{21}=6\sqrt{21}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-6\sqrt{21}}{2*-9}=\frac{-24-6\sqrt{21}}{-18} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+6\sqrt{21}}{2*-9}=\frac{-24+6\sqrt{21}}{-18} $
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