8(c+2)-2(2c-1=2(6c+5)

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Solution for 8(c+2)-2(2c-1=2(6c+5) equation:



8(c+2)-2(2c-1=2(6c+5)
We move all terms to the left:
8(c+2)-2(2c-1-(2(6c+5))=0
We multiply parentheses
8c-2(2c-1-(2(6c+5))+16=0

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