0.3(2y-3)=y+2

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Solution for 0.3(2y-3)=y+2 equation: 



0.3(2y-3)=y+2

We move all terms to the left:

0.3(2y-3)-(y+2)=0

We multiply parentheses

0.6y-(y+2)-0.9=0

We get rid of parentheses

0.6y-y-2-0.9=0

We add all the numbers together, and all the variables

-0.4y-2.9=0

We move all terms containing y to the left, all other terms to the right

-0.4y=2.9

y=2.9/-0.4

y=-7+0.1/0.4

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