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28=4-4(5x+2)4x
We move all terms to the left:
28-(4-4(5x+2)4x)=0
We calculate terms in parentheses: -(4-4(5x+2)4x), so:We get rid of parentheses
4-4(5x+2)4x
determiningTheFunctionDomain -4(5x+2)4x+4
We multiply parentheses
-80x^2-32x+4
Back to the equation:
-(-80x^2-32x+4)
80x^2+32x-4+28=0
We add all the numbers together, and all the variables
80x^2+32x+24=0
a = 80; b = 32; c = +24;
Δ = b2-4ac
Δ = 322-4·80·24
Δ = -6656
Delta is less than zero, so there is no solution for the equation
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