(4x+33)=(6x+5)

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Solution for (4x+33)=(6x+5) equation: 



(4x+33)=(6x+5)

We move all terms to the left:

(4x+33)-((6x+5))=0

We get rid of parentheses

4x-((6x+5))+33=0



We calculate terms in parentheses: -((6x+5)), so:

(6x+5)

We get rid of parentheses

6x+5

Back to the equation:

-(6x+5)



We get rid of parentheses

4x-6x-5+33=0

We add all the numbers together, and all the variables

-2x+28=0

We move all terms containing x to the left, all other terms to the right

-2x=-28

x=-28/-2

x=+14

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