x(7x-4)=(7x+6)(x-1)

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Solution for x(7x-4)=(7x+6)(x-1) equation: 



x(7x-4)=(7x+6)(x-1)

We move all terms to the left:

x(7x-4)-((7x+6)(x-1))=0

We multiply parentheses

7x^2-4x-((7x+6)(x-1))=0

We multiply parentheses ..

7x^2-((+7x^2-7x+6x-6))-4x=0



We calculate terms in parentheses: -((+7x^2-7x+6x-6)), so:

(+7x^2-7x+6x-6)

We get rid of parentheses

7x^2-7x+6x-6

We add all the numbers together, and all the variables

7x^2-1x-6

Back to the equation:

-(7x^2-1x-6)



We add all the numbers together, and all the variables

7x^2-4x-(7x^2-1x-6)=0

We get rid of parentheses

7x^2-7x^2-4x+1x+6=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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