8x+7/5x+10=1

Solution for 8x+7/5x+10=1 equation:

8x+7/5x+10=1

We move all terms to the left:

8x+7/5x+10-(1)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We add all the numbers together, and all the variables

8x+7/5x+9=0

We multiply all the terms by the denominator


8x*5x+9*5x+7=0

Wy multiply elements

40x^2+45x+7=0

a = 40; b = 45; c = +7;
Δ = b2-4ac
Δ = 452-4·40·7
Δ = 905
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{905}}{2*40}=\frac{-45-\sqrt{905}}{80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{905}}{2*40}=\frac{-45+\sqrt{905}}{80}
$