3x-2(6-x)=7x+(5+x)-6

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Solution for 3x-2(6-x)=7x+(5+x)-6 equation: 



3x-2(6-x)=7x+(5+x)-6

We move all terms to the left:

3x-2(6-x)-(7x+(5+x)-6)=0

We add all the numbers together, and all the variables

3x-2(-1x+6)-(7x+(x+5)-6)=0

We multiply parentheses

3x+2x-(7x+(x+5)-6)-12=0



We calculate terms in parentheses: -(7x+(x+5)-6), so:

7x+(x+5)-6

We get rid of parentheses

7x+x+5-6

We add all the numbers together, and all the variables

8x-1

Back to the equation:

-(8x-1)



We add all the numbers together, and all the variables

5x-(8x-1)-12=0

We get rid of parentheses

5x-8x+1-12=0

We add all the numbers together, and all the variables

-3x-11=0

We move all terms containing x to the left, all other terms to the right

-3x=11

x=11/-3

x=-3+2/3

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