(40/r)-r=6

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Solution for (40/r)-r=6 equation: 


D( r )

r = 0

r = 0

r = 0

r in (-oo:0) U (0:+oo)

40/r-r = 6 // - 6

40/r-r-6 = 0

40*r^-1-1*r^1-6*r^0 = 0

(40*r^0-1*r^2-6*r^1)/(r^1) = 0 // * r^2

r^1*(40*r^0-1*r^2-6*r^1) = 0

r^1

40-r^2-6*r = 0

40-r^2-6*r = 0

DELTA = (-6)^2-(-1*4*40)

DELTA = 196

DELTA > 0

r = (196^(1/2)+6)/(-1*2) or r = (6-196^(1/2))/(-1*2)

r = -10 or r = 4

r in { -10, 4} 

r in { -10, 4 }

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