14-1/5(j-10)=2/5(25-2v)

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Solution for 14-1/5(j-10)=2/5(25-2v) equation: 


x in (-oo:+oo)

14-((1/5)*(j-10)) = (2/5)*(25-(2*v)) // - (2/5)*(25-(2*v))

14-((1/5)*(j-10))-((2/5)*(25-(2*v))) = 0

(-1/5)*(j-10)+(-2/5)*(25-2*v)+14 = 0

14-1/5*(j-10)-2/5*(25-2*v) = 0

14-1/5*(j-10)-2/5*(25-2*v) = 0

4/5*v-1/5*j-8+14 = 0

4/5*v-1/5*j+6 = 0

4/5*v-1/5*j+6 = 0

x belongs to the empty set

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