1/2-7/2a=5/a

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Solution for 1/2-7/2a=5/a equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

1/2-((7/2)*a) = 5/a // - 5/a

1/2-((7/2)*a)-(5/a) = 0

(-7/2)*a-5*a^-1+1/2 = 0

1/2*a^0-7/2*a^1-5*a^-1 = 0

(1/2*a^1-7/2*a^2-5*a^0)/(a^1) = 0 // * a^2

a^1*(1/2*a^1-7/2*a^2-5*a^0) = 0

a^1

(-7/2)*a^2+(1/2)*a-5 = 0

(-7/2)*a^2+(1/2)*a-5 = 0

DELTA = (1/2)^2-(-5*4*(-7/2))

DELTA = -279/4

DELTA < 0

a in { } 

a belongs to the empty set

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