(3x-8)+(3x+4)+(7x-11)=180

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Solution for (3x-8)+(3x+4)+(7x-11)=180 equation: 



(3x-8)+(3x+4)+(7x-11)=180

We move all terms to the left:

(3x-8)+(3x+4)+(7x-11)-(180)=0

We get rid of parentheses

3x+3x+7x-8+4-11-180=0

We add all the numbers together, and all the variables

13x-195=0

We move all terms containing x to the left, all other terms to the right

13x=195

x=195/13

x=15

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