(h)(2)=9.4

Solution for (h)(2)=9.4 equation:

(h)(2)=9.4

We move all terms to the left:

(h)(2)-(9.4)=0

We add all the numbers together, and all the variables

h^2-9.4=0

a = 1; b = 0; c = -9.4;
Δ = b2-4ac
Δ = 02-4·1·(-9.4)
Δ = 37.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{37.6}}{2*1}=\frac{0-\sqrt{37.6}}{2}
=-\frac{\sqrt{}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{37.6}}{2*1}=\frac{0+\sqrt{37.6}}{2}
=\frac{\sqrt{}}{2}
$