(8x-19)=(3x+17)+(2x-12)

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Solution for (8x-19)=(3x+17)+(2x-12) equation: 



(8x-19)=(3x+17)+(2x-12)

We move all terms to the left:

(8x-19)-((3x+17)+(2x-12))=0

We get rid of parentheses

8x-((3x+17)+(2x-12))-19=0



We calculate terms in parentheses: -((3x+17)+(2x-12)), so:

(3x+17)+(2x-12)

We get rid of parentheses

3x+2x+17-12

We add all the numbers together, and all the variables

5x+5

Back to the equation:

-(5x+5)



We get rid of parentheses

8x-5x-5-19=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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