(7y+20)=(4y+38)

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Solution for (7y+20)=(4y+38) equation: 



(7y+20)=(4y+38)

We move all terms to the left:

(7y+20)-((4y+38))=0

We get rid of parentheses

7y-((4y+38))+20=0



We calculate terms in parentheses: -((4y+38)), so:

(4y+38)

We get rid of parentheses

4y+38

Back to the equation:

-(4y+38)



We get rid of parentheses

7y-4y-38+20=0

We add all the numbers together, and all the variables

3y-18=0

We move all terms containing y to the left, all other terms to the right

3y=18

y=18/3

y=6

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