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(3x-28)=(x+2)
We move all terms to the left:
(3x-28)-((x+2))=0
We get rid of parentheses
3x-((x+2))-28=0
We calculate terms in parentheses: -((x+2)), so:We get rid of parentheses
(x+2)
We get rid of parentheses
x+2
Back to the equation:
-(x+2)
3x-x-2-28=0
We add all the numbers together, and all the variables
2x-30=0
We move all terms containing x to the left, all other terms to the right
2x=30
x=30/2
x=15
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