(3)/(4)(2m-5)=2(3m-4)-(5)/(6)m

Solution for (3)/(4)(2m-5)=2(3m-4)-(5)/(6)m equation:

(3)/(4)(2m-5)=2(3m-4)-(5)/(6)m

We move all terms to the left:

(3)/(4)(2m-5)-(2(3m-4)-(5)/(6)m)=0


Domain of the equation: 4(2m-5)!=0

m∈R



Domain of the equation: 6m)!=0

m!=0/1

m!=0

m∈R


We calculate fractions


18m/(-120m^2+8m)+(-(6m-20m2)/(-120m^2+8m)=0


We calculate terms in parentheses: +(-(6m-20m2)/(-120m^2+8m), so:

-(6m-20m2)/(-120m^2+8m

We add all the numbers together, and all the variables

-(+6m-20m^2)/(-120m^2+8m

We multiply all the terms by the denominator


-(+6m-20m^2)

We get rid of parentheses

20m^2-6m

Back to the equation:

+(20m^2-6m)


We get rid of parentheses

18m/(-120m^2+8m)+20m^2-6m=0

We multiply all the terms by the denominator


20m^2*(-120m^2+8m)-6m*(-120m^2+8m)+18m=0

We multiply parentheses

20m^2*(-120m^2+8m)+720m^3-48m^2+18m=0

We do not support empression: m^3