12-4(x+1)=6(x-2)

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Solution for 12-4(x+1)=6(x-2) equation: 



12-4(x+1)=6(x-2)

We move all terms to the left:

12-4(x+1)-(6(x-2))=0

We multiply parentheses

-4x-(6(x-2))-4+12=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

-4x-(6x-12)+8=0

We get rid of parentheses

-4x-6x+12+8=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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