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x2-29x-602=0
We add all the numbers together, and all the variables
x^2-29x-602=0
a = 1; b = -29; c = -602;
Δ = b2-4ac
Δ = -292-4·1·(-602)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-57}{2*1}=\frac{-28}{2} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+57}{2*1}=\frac{86}{2} =43 $
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