(3x+40)+(4x-12)=90

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Solution for (3x+40)+(4x-12)=90 equation: 



(3x+40)+(4x-12)=90

We move all terms to the left:

(3x+40)+(4x-12)-(90)=0

We get rid of parentheses

3x+4x+40-12-90=0

We add all the numbers together, and all the variables

7x-62=0

We move all terms containing x to the left, all other terms to the right

7x=62

x=62/7

x=8+6/7

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