(2y+3)/(y-3)=5

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Solution for (2y+3)/(y-3)=5 equation: 



(2y+3)/(y-3)=5

We move all terms to the left:

(2y+3)/(y-3)-(5)=0



Domain of the equation: (y-3)!=0

We move all terms containing y to the left, all other terms to the right

y!=3

y∈R



We multiply all the terms by the denominator


(2y+3)-5*(y-3)=0

We multiply parentheses

(2y+3)-5y+15=0

We get rid of parentheses

2y-5y+3+15=0

We add all the numbers together, and all the variables

-3y+18=0

We move all terms containing y to the left, all other terms to the right

-3y=-18

y=-18/-3

y=+6

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