2/3(6-3x)=1/2(-4x+8)

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Solution for 2/3(6-3x)=1/2(-4x+8) equation: 



2/3(6-3x)=1/2(-4x+8)

We move all terms to the left:

2/3(6-3x)-(1/2(-4x+8))=0



Domain of the equation: 3(6-3x)!=0

x∈R





Domain of the equation: 2(-4x+8))!=0

x∈R



We add all the numbers together, and all the variables

2/3(-3x+6)-(1/2(-4x+8))=0

We calculate fractions


(4x(-)/(3(-3x+6)*2(-4x+8)))+(-3x0/(3(-3x+6)*2(-4x+8)))=0



We calculate terms in parentheses: +(4x(-)/(3(-3x+6)*2(-4x+8))), so:

4x(-)/(3(-3x+6)*2(-4x+8))

We add all the numbers together, and all the variables

4x0/(3(-3x+6)*2(-4x+8))

We multiply all the terms by the denominator


4x0

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-3x0/(3(-3x+6)*2(-4x+8))), so:

-3x0/(3(-3x+6)*2(-4x+8))

We multiply all the terms by the denominator


-3x0

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

4x-3x=0

We add all the numbers together, and all the variables

x=0

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