2(5x-20)=10+(x-20)

Solution for 2(5x-20)=10+(x-20) equation:

2(5x-20)=10+(x-20)

We move all terms to the left:

2(5x-20)-(10+(x-20))=0

We multiply parentheses

10x-(10+(x-20))-40=0


We calculate terms in parentheses: -(10+(x-20)), so:

10+(x-20)

determiningTheFunctionDomain
(x-20)+10

We get rid of parentheses

x-20+10

We add all the numbers together, and all the variables

x-10

Back to the equation:

-(x-10)


We get rid of parentheses

10x-x+10-40=0

We add all the numbers together, and all the variables

9x-30=0

We move all terms containing x to the left, all other terms to the right

9x=30

x=30/9

x=3+1/3