(3x+3)+(x-4)=46

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Solution for (3x+3)+(x-4)=46 equation: 



(3x+3)+(x-4)=46

We move all terms to the left:

(3x+3)+(x-4)-(46)=0

We get rid of parentheses

3x+x+3-4-46=0

We add all the numbers together, and all the variables

4x-47=0

We move all terms containing x to the left, all other terms to the right

4x=47

x=47/4

x=11+3/4

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