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3/2x+5x=13
We move all terms to the left:
3/2x+5x-(13)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
5x+3/2x-13=0
We multiply all the terms by the denominator
5x*2x-13*2x+3=0
Wy multiply elements
10x^2-26x+3=0
a = 10; b = -26; c = +3;
Δ = b2-4ac
Δ = -262-4·10·3
Δ = 556
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{556}=\sqrt{4*139}=\sqrt{4}*\sqrt{139}=2\sqrt{139}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-2\sqrt{139}}{2*10}=\frac{26-2\sqrt{139}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+2\sqrt{139}}{2*10}=\frac{26+2\sqrt{139}}{20} $
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