(2x-5)+(20-x)+(x+5)=180

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Solution for (2x-5)+(20-x)+(x+5)=180 equation: 



(2x-5)+(20-x)+(x+5)=180

We move all terms to the left:

(2x-5)+(20-x)+(x+5)-(180)=0

We add all the numbers together, and all the variables

(2x-5)+(-1x+20)+(x+5)-180=0

We get rid of parentheses

2x-1x+x-5+20+5-180=0

We add all the numbers together, and all the variables

2x-160=0

We move all terms containing x to the left, all other terms to the right

2x=160

x=160/2

x=80

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