-1/2(x-4)+3x=2x-5+6x

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Solution for -1/2(x-4)+3x=2x-5+6x equation: 



-1/2(x-4)+3x=2x-5+6x

We move all terms to the left:

-1/2(x-4)+3x-(2x-5+6x)=0



Domain of the equation: 2(x-4)!=0

x∈R



We add all the numbers together, and all the variables

-1/2(x-4)+3x-(8x-5)=0

We add all the numbers together, and all the variables

3x-1/2(x-4)-(8x-5)=0

We get rid of parentheses

3x-1/2(x-4)-8x+5=0

We multiply all the terms by the denominator


3x*2(x-4)-8x*2(x-4)+5*2(x-4)-1=0

Wy multiply elements

6x^2(x-16x^2(x+10x(x-1=0

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