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(3x)(8x+4)=180
We move all terms to the left:
(3x)(8x+4)-(180)=0
We multiply parentheses
24x^2+12x-180=0
a = 24; b = 12; c = -180;
Δ = b2-4ac
Δ = 122-4·24·(-180)
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{17424}=132$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-132}{2*24}=\frac{-144}{48} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+132}{2*24}=\frac{120}{48} =2+1/2 $
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