3(1-u)+19=4(u-6)-3

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Solution for 3(1-u)+19=4(u-6)-3 equation: 



3(1-u)+19=4(u-6)-3

We move all terms to the left:

3(1-u)+19-(4(u-6)-3)=0

We add all the numbers together, and all the variables

3(-1u+1)-(4(u-6)-3)+19=0

We multiply parentheses

-3u-(4(u-6)-3)+3+19=0



We calculate terms in parentheses: -(4(u-6)-3), so:

4(u-6)-3

We multiply parentheses

4u-24-3

We add all the numbers together, and all the variables

4u-27

Back to the equation:

-(4u-27)



We add all the numbers together, and all the variables

-3u-(4u-27)+22=0

We get rid of parentheses

-3u-4u+27+22=0

We add all the numbers together, and all the variables

-7u+49=0

We move all terms containing u to the left, all other terms to the right

-7u=-49

u=-49/-7

u=+7

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