If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(12/5)x=(3/5)
We move all terms to the left:
(12/5)x-((3/5))=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+12/5)x-((+3/5))=0
We multiply parentheses
12x^2-((+3/5))=0
We multiply all the terms by the denominator
12x^2*5))-((+3=0
Wy multiply elements
60x^3+3=0
We do not support expression: x^3
| 3(1-u)+19=4(u-6)-3 | | 3u=4u-11 | | 4x+8*2x-3=180 | | 86=16x-10 | | (0.1x-22)=(0.3x-54) | | 4-(2x+4)=-2x+4 | | .1/2x+5=x | | 2/6+x=4/6 | | 6/10+m=8/10 | | 246=-w+146 | | 246=-w+1146 | | 18=6b-12 | | 10d+5=-10 | | 3e-2=E+10 | | 91=7g | | (x+20)+(3x-18)=180 | | 10b=3b+7b | | P(8.r)=36 | | 17=2-5y | | 2z+14=28 | | 2(3x+2)+9=-7x | | 7x+5=x-3=8 | | -3=(18-3x)/4 | | P(9.r)=3024 | | -3=18-3x/4 | | x*x+1=10 | | 5/3=12x/x | | 10x*2=5x+20 | | 5d=20= | | F(x)=6(-6)/2(-6)+1 | | F(x)=6(1)/2(1)+1 | | 16-4x=12. |