(3/2)x+2.3-(1/2)x=4.3+x

Solution for (3/2)x+2.3-(1/2)x=4.3+x equation:

(3/2)x+2.3-(1/2)x=4.3+x

We move all terms to the left:

(3/2)x+2.3-(1/2)x-(4.3+x)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/2)x-(+1/2)x-(x+4.3)+2.3=0

We multiply parentheses

3x^2-x^2-(x+4.3)+2.3=0

We get rid of parentheses

3x^2-x^2-x-4.3+2.3=0

We add all the numbers together, and all the variables

2x^2-1x-2=0

a = 2; b = -1; c = -2;
Δ = b2-4ac
Δ = -12-4·2·(-2)
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{17}}{2*2}=\frac{1-\sqrt{17}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{17}}{2*2}=\frac{1+\sqrt{17}}{4}
$