10(2+2)-y=2(8y-8)

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Solution for 10(2+2)-y=2(8y-8) equation: 



10(2+2)-y=2(8y-8)

We move all terms to the left:

10(2+2)-y-(2(8y-8))=0

We add all the numbers together, and all the variables

-y-(2(8y-8))+104=0

We add all the numbers together, and all the variables

-1y-(2(8y-8))+104=0



We calculate terms in parentheses: -(2(8y-8)), so:

2(8y-8)

We multiply parentheses

16y-16

Back to the equation:

-(16y-16)



We get rid of parentheses

-1y-16y+16+104=0

We add all the numbers together, and all the variables

-17y+120=0

We move all terms containing y to the left, all other terms to the right

-17y=-120

y=-120/-17

y=7+1/17

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